Base | Representation |
---|---|
bin | 101110101111100000010… |
… | …001010110000000101111 |
3 | 102101001222222212220001111 |
4 | 232233200101112000233 |
5 | 410111341410304403 |
6 | 10455341515252451 |
7 | 451031624551501 |
oct | 56574021260057 |
9 | 12331888786044 |
10 | 3212103213103 |
11 | 1029277585034 |
12 | 43a63aa4a127 |
13 | 1a3b914b0a25 |
14 | b16765c1d71 |
15 | 5884a52556d |
hex | 2ebe045602f |
3212103213103 has 4 divisors (see below), whose sum is σ = 3264760642888. Its totient is φ = 3159445783320.
The previous prime is 3212103213101. The next prime is 3212103213107. The reversal of 3212103213103 is 3013123012123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3212103213103 - 21 = 3212103213101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3212103213101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26328714801 + ... + 26328714922.
It is an arithmetic number, because the mean of its divisors is an integer number (816190160722).
Almost surely, 23212103213103 is an apocalyptic number.
3212103213103 is a deficient number, since it is larger than the sum of its proper divisors (52657429785).
3212103213103 is an equidigital number, since it uses as much as digits as its factorization.
3212103213103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52657429784.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 3212103213103 its reverse (3013123012123), we get a palindrome (6225226225226).
The spelling of 3212103213103 in words is "three trillion, two hundred twelve billion, one hundred three million, two hundred thirteen thousand, one hundred three".
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