Base | Representation |
---|---|
bin | 100100100001001000101010… |
… | …1001111101010010011011010 |
3 | 1120010022201001012221111202222 |
4 | 1021002101111033222103122 |
5 | 314100230113220131132 |
6 | 3055055230313024042 |
7 | 124441622410060625 |
oct | 11102212517522332 |
9 | 1503281035844688 |
10 | 321213444302042 |
11 | 93391947322776 |
12 | 300393986b5022 |
13 | 10a303b4428556 |
14 | 5946b56960dbc |
15 | 2720773847412 |
hex | 12424553ea4da |
321213444302042 has 4 divisors (see below), whose sum is σ = 481820166453066. Its totient is φ = 160606722151020.
The previous prime is 321213444301973. The next prime is 321213444302119. The reversal of 321213444302042 is 240203444312123.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 164643055231561 + 156570389070481 = 12831331^2 + 12512809^2 .
It is a junction number, because it is equal to n+sod(n) for n = 321213444301993 and 321213444302011.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80303361075509 + ... + 80303361075512.
Almost surely, 2321213444302042 is an apocalyptic number.
321213444302042 is a deficient number, since it is larger than the sum of its proper divisors (160606722151024).
321213444302042 is a wasteful number, since it uses less digits than its factorization.
321213444302042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160606722151023.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 321213444302042 its reverse (240203444312123), we get a palindrome (561416888614165).
The spelling of 321213444302042 in words is "three hundred twenty-one trillion, two hundred thirteen billion, four hundred forty-four million, three hundred two thousand, forty-two".
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