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32121411307 is a prime number
BaseRepresentation
bin11101111010100101…
…011101011011101011
310001220121002202121021
4131322211131123223
51011241040130212
622431213153311
72214666330316
oct357245353353
9101817082537
1032121411307
1112693776817
12628548b837
13304ba3b86b
1417aa0a997d
15c7eec0307
hex77a95d6eb

32121411307 has 2 divisors, whose sum is σ = 32121411308. Its totient is φ = 32121411306.

The previous prime is 32121411271. The next prime is 32121411383. The reversal of 32121411307 is 70311412123.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 32121411307 - 211 = 32121409259 is a prime.

It is not a weakly prime, because it can be changed into another prime (32121411397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16060705653 + 16060705654.

It is an arithmetic number, because the mean of its divisors is an integer number (16060705654).

Almost surely, 232121411307 is an apocalyptic number.

32121411307 is a deficient number, since it is larger than the sum of its proper divisors (1).

32121411307 is an equidigital number, since it uses as much as digits as its factorization.

32121411307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 32121411307 in words is "thirty-two billion, one hundred twenty-one million, four hundred eleven thousand, three hundred seven".