Search a number
-
+
32122168203133 is a prime number
BaseRepresentation
bin1110100110111000001100…
…11011001101011101111101
311012201211221010120100111101
413103130012123031131331
513202242200030000013
6152152415332453101
76523515162444511
oct723340633153575
9135654833510441
1032122168203133
11a264a31589078
1237295a917a191
1314c01521384c8
147d0a15104141
153aa8882978dd
hex1d37066cd77d

32122168203133 has 2 divisors, whose sum is σ = 32122168203134. Its totient is φ = 32122168203132.

The previous prime is 32122168203121. The next prime is 32122168203157. The reversal of 32122168203133 is 33130286122123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24146983225764 + 7975184977369 = 4913958^2 + 2824037^2 .

It is a cyclic number.

It is not a de Polignac number, because 32122168203133 - 229 = 32121631332221 is a prime.

It is a super-3 number, since 3×321221682031333 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32122168203092 and 32122168203101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32122168203163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16061084101566 + 16061084101567.

It is an arithmetic number, because the mean of its divisors is an integer number (16061084101567).

Almost surely, 232122168203133 is an apocalyptic number.

It is an amenable number.

32122168203133 is a deficient number, since it is larger than the sum of its proper divisors (1).

32122168203133 is an equidigital number, since it uses as much as digits as its factorization.

32122168203133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 37.

The spelling of 32122168203133 in words is "thirty-two trillion, one hundred twenty-two billion, one hundred sixty-eight million, two hundred three thousand, one hundred thirty-three".