Base | Representation |
---|---|
bin | 1011111101111001… |
… | …0101010110000001 |
3 | 22021212200211100211 |
4 | 2333132111112001 |
5 | 23034333300001 |
6 | 1250432514121 |
7 | 142414643446 |
oct | 27736252601 |
9 | 8255624324 |
10 | 3212400001 |
11 | 13a9352738 |
12 | 7579ab941 |
13 | 3c26c0905 |
14 | 2268d59cd |
15 | 13c04c351 |
hex | bf795581 |
3212400001 has 2 divisors, whose sum is σ = 3212400002. Its totient is φ = 3212400000.
The previous prime is 3212399959. The next prime is 3212400029. The reversal of 3212400001 is 1000042123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2997015025 + 215384976 = 54745^2 + 14676^2 .
It is an emirp because it is prime and its reverse (1000042123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3212400001 - 211 = 3212397953 is a prime.
It is not a weakly prime, because it can be changed into another prime (3212400031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606200000 + 1606200001.
It is an arithmetic number, because the mean of its divisors is an integer number (1606200001).
Almost surely, 23212400001 is an apocalyptic number.
It is an amenable number.
3212400001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212400001 is an equidigital number, since it uses as much as digits as its factorization.
3212400001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 3212400001 is about 56678.0380835470. The cubic root of 3212400001 is about 1475.5135625833.
Adding to 3212400001 its reverse (1000042123), we get a palindrome (4212442124).
The spelling of 3212400001 in words is "three billion, two hundred twelve million, four hundred thousand, one".
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