Base | Representation |
---|---|
bin | 11101111010110000… |
… | …110111011011100101 |
3 | 10001220210201200012202 |
4 | 131322300313123211 |
5 | 1011242321321011 |
6 | 22431401224245 |
7 | 2215033622612 |
oct | 357260673345 |
9 | 101823650182 |
10 | 32124401381 |
11 | 12695429256 |
12 | 6286492085 |
13 | 304c547837 |
14 | 17aa647509 |
15 | c803b123b |
hex | 77ac376e5 |
32124401381 has 2 divisors, whose sum is σ = 32124401382. Its totient is φ = 32124401380.
The previous prime is 32124401377. The next prime is 32124401473. The reversal of 32124401381 is 18310442123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26735520100 + 5388881281 = 163510^2 + 73409^2 .
It is an emirp because it is prime and its reverse (18310442123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32124401381 - 22 = 32124401377 is a prime.
It is a super-2 number, since 2×321244013812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32124401081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16062200690 + 16062200691.
It is an arithmetic number, because the mean of its divisors is an integer number (16062200691).
Almost surely, 232124401381 is an apocalyptic number.
It is an amenable number.
32124401381 is a deficient number, since it is larger than the sum of its proper divisors (1).
32124401381 is an equidigital number, since it uses as much as digits as its factorization.
32124401381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
The spelling of 32124401381 in words is "thirty-two billion, one hundred twenty-four million, four hundred one thousand, three hundred eighty-one".
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