3212511214331 has 2 divisors, whose sum is σ = 3212511214332. Its totient is φ = 3212511214330.

The previous prime is 3212511214327. The next prime is 3212511214333. The reversal of 3212511214331 is 1334121152123.

It is a strong prime.

It is an emirp because it is prime and its reverse (1334121152123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3212511214331 - 2² = 3212511214327 is a prime.

It is a super-2 number, since 2×3212511214331² (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 3212511214333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3212511214294 and 3212511214303.

It is not a weakly prime, because it can be changed into another prime (3212511214333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606255607165 + 1606255607166.

It is an arithmetic number, because the mean of its divisors is an integer number (1606255607166).

Almost surely, 2^{3212511214331} is an apocalyptic number.

3212511214331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212511214331 is an equidigital number, since it uses as much as digits as its factorization.

3212511214331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 29.

Adding to 3212511214331 its reverse (1334121152123), we get a palindrome (4546632366454).

The spelling of 3212511214331 in words is "three trillion, two hundred twelve billion, five hundred eleven million, two hundred fourteen thousand, three hundred thirty-one".