Base | Representation |
---|---|
bin | 101110101111111001000… |
… | …111010011100101101001 |
3 | 102101010002001011110211202 |
4 | 232233321013103211221 |
5 | 410113220110342022 |
6 | 10455451124533545 |
7 | 451045145361152 |
oct | 56577107234551 |
9 | 12333061143752 |
10 | 3212520012137 |
11 | 1029470884347 |
12 | 43a7365512b5 |
13 | 1a3c29954787 |
14 | b16b5aba929 |
15 | 58871e06592 |
hex | 2ebf91d3969 |
3212520012137 has 2 divisors, whose sum is σ = 3212520012138. Its totient is φ = 3212520012136.
The previous prime is 3212520012083. The next prime is 3212520012139. The reversal of 3212520012137 is 7312100252123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1960394819881 + 1252125192256 = 1400141^2 + 1118984^2 .
It is a cyclic number.
It is not a de Polignac number, because 3212520012137 - 212 = 3212520008041 is a prime.
Together with 3212520012139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3212520012139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606260006068 + 1606260006069.
It is an arithmetic number, because the mean of its divisors is an integer number (1606260006069).
Almost surely, 23212520012137 is an apocalyptic number.
It is an amenable number.
3212520012137 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212520012137 is an equidigital number, since it uses as much as digits as its factorization.
3212520012137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
The spelling of 3212520012137 in words is "three trillion, two hundred twelve billion, five hundred twenty million, twelve thousand, one hundred thirty-seven".
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