Base | Representation |
---|---|
bin | 1110100111000111100110… |
… | …00100011100100100000111 |
3 | 11012202122021011000000102021 |
4 | 13103203303010130210013 |
5 | 13202411111422400033 |
6 | 152200303424424011 |
7 | 6524230043464525 |
oct | 723436304344407 |
9 | 135678234000367 |
10 | 32130433403143 |
11 | a268493021189 |
12 | 372b115178007 |
13 | 14c0b6b5b36ba |
14 | 7d119aac3315 |
15 | 3aabbdbcab2d |
hex | 1d38f311c907 |
32130433403143 has 2 divisors, whose sum is σ = 32130433403144. Its totient is φ = 32130433403142.
The previous prime is 32130433402973. The next prime is 32130433403161. The reversal of 32130433403143 is 34130433403123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32130433403143 - 213 = 32130433394951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32130433403099 and 32130433403108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32130433463143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065216701571 + 16065216701572.
It is an arithmetic number, because the mean of its divisors is an integer number (16065216701572).
Almost surely, 232130433403143 is an apocalyptic number.
32130433403143 is a deficient number, since it is larger than the sum of its proper divisors (1).
32130433403143 is an equidigital number, since it uses as much as digits as its factorization.
32130433403143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 32130433403143 its reverse (34130433403123), we get a palindrome (66260866806266).
The spelling of 32130433403143 in words is "thirty-two trillion, one hundred thirty billion, four hundred thirty-three million, four hundred three thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •