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3213103001993 is a prime number
BaseRepresentation
bin101110110000011011110…
…111001111000110001001
3102101011120200011102120122
4232300123313033012021
5410120413332030433
610500025032233025
7451065454613063
oct56603367170611
912334520142518
103213103001993
11102973a974245
1243a87983b775
131a3cc0675aa1
14b172d2b6733
15588a81b4198
hex2ec1bdcf189

3213103001993 has 2 divisors, whose sum is σ = 3213103001994. Its totient is φ = 3213103001992.

The previous prime is 3213103001981. The next prime is 3213103002071. The reversal of 3213103001993 is 3991003013123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2305757214784 + 907345787209 = 1518472^2 + 952547^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3213103001993 is a prime.

It is not a weakly prime, because it can be changed into another prime (3213103001903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606551500996 + 1606551500997.

It is an arithmetic number, because the mean of its divisors is an integer number (1606551500997).

Almost surely, 23213103001993 is an apocalyptic number.

It is an amenable number.

3213103001993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3213103001993 is an equidigital number, since it uses as much as digits as its factorization.

3213103001993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 3213103001993 in words is "three trillion, two hundred thirteen billion, one hundred three million, one thousand, nine hundred ninety-three".