Base | Representation |
---|---|
bin | 101110110000011100011… |
… | …110010011100110001101 |
3 | 102101011121101102210000220 |
4 | 232300130132103212031 |
5 | 410120423442302140 |
6 | 10500030035541553 |
7 | 451065640641225 |
oct | 56603436234615 |
9 | 12334541383026 |
10 | 3213113244045 |
11 | 102974572a251 |
12 | 43a88115a8b9 |
13 | 1a3cc2820883 |
14 | b17307c1085 |
15 | 588a9038bd0 |
hex | 2ec1c79398d |
3213113244045 has 32 divisors (see below), whose sum is σ = 5269321728000. Its totient is φ = 1671013291584.
The previous prime is 3213113244043. The next prime is 3213113244083. The reversal of 3213113244045 is 5404423113123.
It is not a de Polignac number, because 3213113244045 - 21 = 3213113244043 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3213113243997 and 3213113244015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213113244043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3771885 + ... + 4544594.
It is an arithmetic number, because the mean of its divisors is an integer number (164666304000).
Almost surely, 23213113244045 is an apocalyptic number.
It is an amenable number.
3213113244045 is a deficient number, since it is larger than the sum of its proper divisors (2056208483955).
3213113244045 is a wasteful number, since it uses less digits than its factorization.
3213113244045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8317129.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 3213113244045 its reverse (5404423113123), we get a palindrome (8617536357168).
The spelling of 3213113244045 in words is "three trillion, two hundred thirteen billion, one hundred thirteen million, two hundred forty-four thousand, forty-five".
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