Base | Representation |
---|---|
bin | 101110110000011100111… |
… | …000110110010100011101 |
3 | 102101011121212112021120102 |
4 | 232300130320312110131 |
5 | 410120432232431023 |
6 | 10500030445030445 |
7 | 451066054040651 |
oct | 56603470662435 |
9 | 12334555467512 |
10 | 3213120202013 |
11 | 1029749651937 |
12 | 43a883555425 |
13 | 1a3cc40b8907 |
14 | b17316b2a61 |
15 | 588a9960628 |
hex | 2ec1ce3651d |
3213120202013 has 4 divisors (see below), whose sum is σ = 3216949905120. Its totient is φ = 3209290498908.
The previous prime is 3213120201979. The next prime is 3213120202031. The reversal of 3213120202013 is 3102020213123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3213120202013 - 214 = 3213120185629 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213120202043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1914850295 + ... + 1914851972.
It is an arithmetic number, because the mean of its divisors is an integer number (804237476280).
Almost surely, 23213120202013 is an apocalyptic number.
It is an amenable number.
3213120202013 is a deficient number, since it is larger than the sum of its proper divisors (3829703107).
3213120202013 is an equidigital number, since it uses as much as digits as its factorization.
3213120202013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3829703106.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 3213120202013 its reverse (3102020213123), we get a palindrome (6315140415136).
The spelling of 3213120202013 in words is "three trillion, two hundred thirteen billion, one hundred twenty million, two hundred two thousand, thirteen".
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