Base | Representation |
---|---|
bin | 1110100111001001010001… |
… | …01100011110101101100111 |
3 | 11012202201120211220211222022 |
4 | 13103210220230132231213 |
5 | 13202414432232341101 |
6 | 152200533004053355 |
7 | 6524261246630651 |
oct | 723445054365547 |
9 | 135681524824868 |
10 | 32131333090151 |
11 | a26890495a369 |
12 | 372b32653425b |
13 | 14c0c82aca789 |
14 | 7d124439b6d1 |
15 | 3aac22b94a1b |
hex | 1d3928b1eb67 |
32131333090151 has 2 divisors, whose sum is σ = 32131333090152. Its totient is φ = 32131333090150.
The previous prime is 32131333090127. The next prime is 32131333090211. The reversal of 32131333090151 is 15109033313123.
It is a weak prime.
It is an emirp because it is prime and its reverse (15109033313123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32131333090151 - 210 = 32131333089127 is a prime.
It is a super-2 number, since 2×321313330901512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32131333090121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065666545075 + 16065666545076.
It is an arithmetic number, because the mean of its divisors is an integer number (16065666545076).
Almost surely, 232131333090151 is an apocalyptic number.
32131333090151 is a deficient number, since it is larger than the sum of its proper divisors (1).
32131333090151 is an equidigital number, since it uses as much as digits as its factorization.
32131333090151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21870, while the sum is 35.
The spelling of 32131333090151 in words is "thirty-two trillion, one hundred thirty-one billion, three hundred thirty-three million, ninety thousand, one hundred fifty-one".
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