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32132412234257 is a prime number
BaseRepresentation
bin1110100111001011010010…
…00001000101101000010001
311012202211101001112001101112
413103211221001011220101
513202424140012444012
6152201232033543105
76524330062331456
oct723455101055021
9135684331461345
1032132412234257
11a26930901a2a5
12372b587a14a95
1314c10c555859a
147d130782b82d
153aac877ab122
hex1d3969045a11

32132412234257 has 2 divisors, whose sum is σ = 32132412234258. Its totient is φ = 32132412234256.

The previous prime is 32132412234233. The next prime is 32132412234259. The reversal of 32132412234257 is 75243221423123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30631454015761 + 1500958218496 = 5534569^2 + 1225136^2 .

It is a cyclic number.

It is not a de Polignac number, because 32132412234257 - 232 = 32128117266961 is a prime.

Together with 32132412234259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (32132412234259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16066206117128 + 16066206117129.

It is an arithmetic number, because the mean of its divisors is an integer number (16066206117129).

Almost surely, 232132412234257 is an apocalyptic number.

It is an amenable number.

32132412234257 is a deficient number, since it is larger than the sum of its proper divisors (1).

32132412234257 is an equidigital number, since it uses as much as digits as its factorization.

32132412234257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 483840, while the sum is 41.

The spelling of 32132412234257 in words is "thirty-two trillion, one hundred thirty-two billion, four hundred twelve million, two hundred thirty-four thousand, two hundred fifty-seven".