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32133433139 is a prime number
BaseRepresentation
bin11101111011010011…
…010100011100110011
310001221102201112110022
4131323103110130303
51011302124330024
622432322554055
72215203450353
oct357323243463
9101842645408
1032133433139
111269a537a15
12628950892b
13305138a782
1417ab918b63
15c8109735e
hex77b4d4733

32133433139 has 2 divisors, whose sum is σ = 32133433140. Its totient is φ = 32133433138.

The previous prime is 32133433121. The next prime is 32133433141. The reversal of 32133433139 is 93133433123.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32133433139 is a prime.

Together with 32133433141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 32133433099 and 32133433108.

It is not a weakly prime, because it can be changed into another prime (32133433169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16066716569 + 16066716570.

It is an arithmetic number, because the mean of its divisors is an integer number (16066716570).

Almost surely, 232133433139 is an apocalyptic number.

32133433139 is a deficient number, since it is larger than the sum of its proper divisors (1).

32133433139 is an equidigital number, since it uses as much as digits as its factorization.

32133433139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 52488, while the sum is 35.

The spelling of 32133433139 in words is "thirty-two billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred thirty-nine".