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32134314554071 is a prime number
BaseRepresentation
bin1110100111001110110100…
…11001110111001011010111
311012210000021122001220120221
413103213122121313023113
513202442034011212241
6152202144511135211
76524425161642412
oct723473231671327
9135700248056527
1032134314554071
11a26a0a490a334
12372ba18b14507
1314c13396c2002
147d144833ab79
153aad497c65d1
hex1d39da6772d7

32134314554071 has 2 divisors, whose sum is σ = 32134314554072. Its totient is φ = 32134314554070.

The previous prime is 32134314554059. The next prime is 32134314554267. The reversal of 32134314554071 is 17045541343123.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32134314554071 is a prime.

It is a super-2 number, since 2×321343145540712 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32134314554471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16067157277035 + 16067157277036.

It is an arithmetic number, because the mean of its divisors is an integer number (16067157277036).

Almost surely, 232134314554071 is an apocalyptic number.

32134314554071 is a deficient number, since it is larger than the sum of its proper divisors (1).

32134314554071 is an equidigital number, since it uses as much as digits as its factorization.

32134314554071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 604800, while the sum is 43.

Adding to 32134314554071 its reverse (17045541343123), we get a palindrome (49179855897194).

The spelling of 32134314554071 in words is "thirty-two trillion, one hundred thirty-four billion, three hundred fourteen million, five hundred fifty-four thousand, seventy-one".