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32134524137 is a prime number
BaseRepresentation
bin11101111011010111…
…011110110011101001
310001221111202222000122
4131323113132303221
51011302414233022
622432402213025
72215215643202
oct357327366351
9101844688018
1032134524137
11126a0112671
126289954175
133051680231
1417abb205a9
15c81210742
hex77b5dece9

32134524137 has 2 divisors, whose sum is σ = 32134524138. Its totient is φ = 32134524136.

The previous prime is 32134524133. The next prime is 32134524139. The reversal of 32134524137 is 73142543123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31839406096 + 295118041 = 178436^2 + 17179^2 .

It is a cyclic number.

It is not a de Polignac number, because 32134524137 - 22 = 32134524133 is a prime.

It is a super-2 number, since 2×321345241372 (a number of 22 digits) contains 22 as substring.

Together with 32134524139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 32134524097 and 32134524106.

It is not a weakly prime, because it can be changed into another prime (32134524133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16067262068 + 16067262069.

It is an arithmetic number, because the mean of its divisors is an integer number (16067262069).

Almost surely, 232134524137 is an apocalyptic number.

It is an amenable number.

32134524137 is a deficient number, since it is larger than the sum of its proper divisors (1).

32134524137 is an equidigital number, since it uses as much as digits as its factorization.

32134524137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 35.

The spelling of 32134524137 in words is "thirty-two billion, one hundred thirty-four million, five hundred twenty-four thousand, one hundred thirty-seven".