Base | Representation |
---|---|
bin | 101110110000110110111… |
… | …010111000110100010001 |
3 | 102101012202022100002010221 |
4 | 232300312322320310101 |
5 | 410122331034203040 |
6 | 10500142045553041 |
7 | 451112636221432 |
oct | 56606672706421 |
9 | 12335668302127 |
10 | 3213556944145 |
11 | 1029953132749 |
12 | 43a985875781 |
13 | 1a4063722c02 |
14 | b17736bd489 |
15 | 588d2e8074a |
hex | 2ec36eb8d11 |
3213556944145 has 4 divisors (see below), whose sum is σ = 3856268332980. Its totient is φ = 2570845555312.
The previous prime is 3213556944107. The next prime is 3213556944203. The reversal of 3213556944145 is 5414496553123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1926630056961 + 1286926887184 = 1388031^2 + 1134428^2 .
It is a cyclic number.
It is not a de Polignac number, because 3213556944145 - 29 = 3213556943633 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3213556944092 and 3213556944101.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321355694410 + ... + 321355694419.
It is an arithmetic number, because the mean of its divisors is an integer number (964067083245).
Almost surely, 23213556944145 is an apocalyptic number.
It is an amenable number.
3213556944145 is a deficient number, since it is larger than the sum of its proper divisors (642711388835).
3213556944145 is an equidigital number, since it uses as much as digits as its factorization.
3213556944145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 642711388834.
The product of its digits is 7776000, while the sum is 52.
The spelling of 3213556944145 in words is "three trillion, two hundred thirteen billion, five hundred fifty-six million, nine hundred forty-four thousand, one hundred forty-five".
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