Base | Representation |
---|---|
bin | 101110110001010010000… |
… | …011100100010110000111 |
3 | 102101020221000222200211201 |
4 | 232301102003210112013 |
5 | 410124244111020143 |
6 | 10500255151443331 |
7 | 451130134660036 |
oct | 56612203442607 |
9 | 12336830880751 |
10 | 3214012204423 |
11 | 102a067111509 |
12 | 43aa92226547 |
13 | 1a4106b41ca7 |
14 | b17b7d4a71d |
15 | 5890ce0c64d |
hex | 2ec520e4587 |
3214012204423 has 2 divisors, whose sum is σ = 3214012204424. Its totient is φ = 3214012204422.
The previous prime is 3214012204397. The next prime is 3214012204441. The reversal of 3214012204423 is 3244022104123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3214012204423 - 225 = 3213978649991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3214012204391 and 3214012204400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3214012204483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607006102211 + 1607006102212.
It is an arithmetic number, because the mean of its divisors is an integer number (1607006102212).
Almost surely, 23214012204423 is an apocalyptic number.
3214012204423 is a deficient number, since it is larger than the sum of its proper divisors (1).
3214012204423 is an equidigital number, since it uses as much as digits as its factorization.
3214012204423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 3214012204423 its reverse (3244022104123), we get a palindrome (6458034308546).
The spelling of 3214012204423 in words is "three trillion, two hundred fourteen billion, twelve million, two hundred four thousand, four hundred twenty-three".
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