Base | Representation |
---|---|
bin | 1110100111011011010111… |
… | …00010001101000001010111 |
3 | 11012210122122122110201120112 |
4 | 13103231223202031001113 |
5 | 13203044324331414221 |
6 | 152205220355153235 |
7 | 6525054020505143 |
oct | 723555342150127 |
9 | 135718578421515 |
10 | 32141044404311 |
11 | a271a38718437 |
12 | 37311968a581b |
13 | 14c1b6ca4bc0b |
14 | 7d18c6054223 |
15 | 3ab0e052b15b |
hex | 1d3b6b88d057 |
32141044404311 has 4 divisors (see below), whose sum is σ = 32141055910992. Its totient is φ = 32141032897632.
The previous prime is 32141044404307. The next prime is 32141044404347. The reversal of 32141044404311 is 11340444014123.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 32141044404311 - 22 = 32141044404307 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32141044406311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1407071 + ... + 8140143.
It is an arithmetic number, because the mean of its divisors is an integer number (8035263977748).
Almost surely, 232141044404311 is an apocalyptic number.
32141044404311 is a deficient number, since it is larger than the sum of its proper divisors (11506681).
32141044404311 is an equidigital number, since it uses as much as digits as its factorization.
32141044404311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11506680.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 32141044404311 its reverse (11340444014123), we get a palindrome (43481488418434).
The spelling of 32141044404311 in words is "thirty-two trillion, one hundred forty-one billion, forty-four million, four hundred four thousand, three hundred eleven".
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