Base | Representation |
---|---|
bin | 100100100010101010010010… |
… | …1010001001001000010111111 |
3 | 1120011001202011222112201112001 |
4 | 1021011110211101021002333 |
5 | 314112143443222444442 |
6 | 3055335421431323131 |
7 | 124463023606536622 |
oct | 11105244521110277 |
9 | 1504052158481461 |
10 | 321423092781247 |
11 | 9346284a435126 |
12 | 30071b475204a7 |
13 | 10a470b5668702 |
14 | 5952d6421ddb9 |
15 | 2725e43d902b7 |
hex | 12455254490bf |
321423092781247 has 2 divisors, whose sum is σ = 321423092781248. Its totient is φ = 321423092781246.
The previous prime is 321423092781227. The next prime is 321423092781257. The reversal of 321423092781247 is 742187290324123.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321423092781247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321423092781227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160711546390623 + 160711546390624.
It is an arithmetic number, because the mean of its divisors is an integer number (160711546390624).
Almost surely, 2321423092781247 is an apocalyptic number.
321423092781247 is a deficient number, since it is larger than the sum of its proper divisors (1).
321423092781247 is an equidigital number, since it uses as much as digits as its factorization.
321423092781247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8128512, while the sum is 55.
The spelling of 321423092781247 in words is "three hundred twenty-one trillion, four hundred twenty-three billion, ninety-two million, seven hundred eighty-one thousand, two hundred forty-seven".
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