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321613351130447 is a prime number
BaseRepresentation
bin100100100100000010111000…
…1100011001001010101001111
31120011201221021102012021100222
41021020011301203021111033
5314123303120342133242
63100003044524141555
7124512540441036425
oct11110056143112517
91504657242167328
10321613351130447
11935265022a7952
12300a29a46978bb
1310a5c01667416c
14595c2525cd115
15272ad7be895d2
hex12481718c954f

321613351130447 has 2 divisors, whose sum is σ = 321613351130448. Its totient is φ = 321613351130446.

The previous prime is 321613351130417. The next prime is 321613351130459. The reversal of 321613351130447 is 744031153316123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 321613351130447 - 212 = 321613351126351 is a prime.

It is a super-2 number, since 2×3216133511304472 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 321613351130398 and 321613351130407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321613351130417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160806675565223 + 160806675565224.

It is an arithmetic number, because the mean of its divisors is an integer number (160806675565224).

Almost surely, 2321613351130447 is an apocalyptic number.

321613351130447 is a deficient number, since it is larger than the sum of its proper divisors (1).

321613351130447 is an equidigital number, since it uses as much as digits as its factorization.

321613351130447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 44.

The spelling of 321613351130447 in words is "three hundred twenty-one trillion, six hundred thirteen billion, three hundred fifty-one million, one hundred thirty thousand, four hundred forty-seven".