Base | Representation |
---|---|
bin | 101110110110110111110… |
… | …010100110110100100001 |
3 | 102101211102022102120120011 |
4 | 232312313302212310201 |
5 | 410224042041021231 |
6 | 10503130511044521 |
7 | 451431643261366 |
oct | 56666762466441 |
9 | 12354368376504 |
10 | 3220014001441 |
11 | 1031666a5a436 |
12 | 440088210741 |
13 | 1a48523b9983 |
14 | b1bc70a646d |
15 | 58b5ec9c9b1 |
hex | 2edb7ca6d21 |
3220014001441 has 8 divisors (see below), whose sum is σ = 3274640403840. Its totient is φ = 3165389262288.
The previous prime is 3220014001433. The next prime is 3220014001459. The reversal of 3220014001441 is 1441004100223.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3220014001441 - 23 = 3220014001433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3220014001241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3858520 + ... + 4618246.
It is an arithmetic number, because the mean of its divisors is an integer number (409330050480).
Almost surely, 23220014001441 is an apocalyptic number.
It is an amenable number.
3220014001441 is a deficient number, since it is larger than the sum of its proper divisors (54626402399).
3220014001441 is an equidigital number, since it uses as much as digits as its factorization.
3220014001441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 831623.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 3220014001441 its reverse (1441004100223), we get a palindrome (4661018101664).
The spelling of 3220014001441 in words is "three trillion, two hundred twenty billion, fourteen million, one thousand, four hundred forty-one".
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