Base | Representation |
---|---|
bin | 101110110111110010101… |
… | …011111100100000011001 |
3 | 102101220222011201202001112 |
4 | 232313302223330200121 |
5 | 410233103020023001 |
6 | 10503412525430105 |
7 | 451465302130313 |
oct | 56676253744031 |
9 | 12356864652045 |
10 | 3221002111001 |
11 | 10320237a1804 |
12 | 44030310b335 |
13 | 1a497c02299c |
14 | b1c7c3da7b3 |
15 | 58bbb8d0cbb |
hex | 2edf2afc819 |
3221002111001 has 2 divisors, whose sum is σ = 3221002111002. Its totient is φ = 3221002111000.
The previous prime is 3221002110973. The next prime is 3221002111003. The reversal of 3221002111001 is 1001112001223.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3221001931225 + 179776 = 1794715^2 + 424^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3221002111001 is a prime.
Together with 3221002111003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3221002111003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610501055500 + 1610501055501.
It is an arithmetic number, because the mean of its divisors is an integer number (1610501055501).
Almost surely, 23221002111001 is an apocalyptic number.
It is an amenable number.
3221002111001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3221002111001 is an equidigital number, since it uses as much as digits as its factorization.
3221002111001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 3221002111001 its reverse (1001112001223), we get a palindrome (4222114112224).
The spelling of 3221002111001 in words is "three trillion, two hundred twenty-one billion, two million, one hundred eleven thousand, one".
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