Base | Representation |
---|---|
bin | 101110111001110001100… |
… | …001101100101001101011 |
3 | 102102010110110222100202221 |
4 | 232321301201230221223 |
5 | 410301432303143201 |
6 | 10504404024334511 |
7 | 451602112035355 |
oct | 56716141545153 |
9 | 12363413870687 |
10 | 3223130131051 |
11 | 1032a15a28766 |
12 | 4407b7914437 |
13 | 1a4c2ab7154c |
14 | b2000c9c0d5 |
15 | 58c936304a1 |
hex | 2ee7186ca6b |
3223130131051 has 2 divisors, whose sum is σ = 3223130131052. Its totient is φ = 3223130131050.
The previous prime is 3223130131043. The next prime is 3223130131061. The reversal of 3223130131051 is 1501310313223.
3223130131051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3223130131051 - 23 = 3223130131043 is a prime.
It is not a weakly prime, because it can be changed into another prime (3223130131061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1611565065525 + 1611565065526.
It is an arithmetic number, because the mean of its divisors is an integer number (1611565065526).
Almost surely, 23223130131051 is an apocalyptic number.
3223130131051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3223130131051 is an equidigital number, since it uses as much as digits as its factorization.
3223130131051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 3223130131051 its reverse (1501310313223), we get a palindrome (4724440444274).
The spelling of 3223130131051 in words is "three trillion, two hundred twenty-three billion, one hundred thirty million, one hundred thirty-one thousand, fifty-one".
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