Base | Representation |
---|---|
bin | 1110101010010110001000… |
… | …00100011001010100100011 |
3 | 11020011020110121102110212001 |
4 | 13111023010010121110203 |
5 | 13211220202341313103 |
6 | 152323242152544431 |
7 | 6535233550214221 |
oct | 725130404312443 |
9 | 136136417373761 |
10 | 32241314010403 |
11 | a300512258593 |
12 | 37486ba9b2117 |
13 | 14cb45c377094 |
14 | 7d66b8c15b11 |
15 | 3ada0d26e01d |
hex | 1d52c4119523 |
32241314010403 has 2 divisors, whose sum is σ = 32241314010404. Its totient is φ = 32241314010402.
The previous prime is 32241314010391. The next prime is 32241314010421. The reversal of 32241314010403 is 30401041314223.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (30401041314223) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32241314010403 - 217 = 32241313879331 is a prime.
It is not a weakly prime, because it can be changed into another prime (32241314010443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16120657005201 + 16120657005202.
It is an arithmetic number, because the mean of its divisors is an integer number (16120657005202).
Almost surely, 232241314010403 is an apocalyptic number.
32241314010403 is a deficient number, since it is larger than the sum of its proper divisors (1).
32241314010403 is an equidigital number, since it uses as much as digits as its factorization.
32241314010403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 32241314010403 its reverse (30401041314223), we get a palindrome (62642355324626).
The spelling of 32241314010403 in words is "thirty-two trillion, two hundred forty-one billion, three hundred fourteen million, ten thousand, four hundred three".
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