Base | Representation |
---|---|
bin | 1110101010011101001100… |
… | …11101011101010011101111 |
3 | 11020011121021022110002012120 |
4 | 13111032212131131103233 |
5 | 13211300442212344101 |
6 | 152325111114004023 |
7 | 6535426640443131 |
oct | 725164635352357 |
9 | 136147238402176 |
10 | 32245112231151 |
11 | a302091253aa6 |
12 | 374939aa16613 |
13 | 14cb91623a691 |
14 | 7d6959443051 |
15 | 3adb81937b36 |
hex | 1d53a675d4ef |
32245112231151 has 12 divisors (see below), whose sum is σ = 44016583713048. Its totient is φ = 20996817263184.
The previous prime is 32245112231149. The next prime is 32245112231183. The reversal of 32245112231151 is 15113221154223.
It is not a de Polignac number, because 32245112231151 - 21 = 32245112231149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32245112231141) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2906530620 + ... + 2906541713.
It is an arithmetic number, because the mean of its divisors is an integer number (3668048642754).
Almost surely, 232245112231151 is an apocalyptic number.
32245112231151 is a deficient number, since it is larger than the sum of its proper divisors (11771471481897).
32245112231151 is an equidigital number, since it uses as much as digits as its factorization.
32245112231151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5813072422 (or 5813072379 counting only the distinct ones).
The product of its digits is 14400, while the sum is 33.
Adding to 32245112231151 its reverse (15113221154223), we get a palindrome (47358333385374).
The spelling of 32245112231151 in words is "thirty-two trillion, two hundred forty-five billion, one hundred twelve million, two hundred thirty-one thousand, one hundred fifty-one".
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