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32245112231317 is a prime number
BaseRepresentation
bin1110101010011101001100…
…11101011101010110010101
311020011121021022110002102201
413111032212131131112111
513211300442212400232
6152325111114004501
76535426640443456
oct725164635352625
9136147238402381
1032245112231317
11a302091254137
12374939aa16731
1314cb91623a78b
147d695944312d
153adb81937be7
hex1d53a675d595

32245112231317 has 2 divisors, whose sum is σ = 32245112231318. Its totient is φ = 32245112231316.

The previous prime is 32245112231287. The next prime is 32245112231333. The reversal of 32245112231317 is 71313221154223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31593853547281 + 651258684036 = 5620841^2 + 807006^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32245112231317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32245112331317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16122556115658 + 16122556115659.

It is an arithmetic number, because the mean of its divisors is an integer number (16122556115659).

Almost surely, 232245112231317 is an apocalyptic number.

It is an amenable number.

32245112231317 is a deficient number, since it is larger than the sum of its proper divisors (1).

32245112231317 is an equidigital number, since it uses as much as digits as its factorization.

32245112231317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 37.

The spelling of 32245112231317 in words is "thirty-two trillion, two hundred forty-five billion, one hundred twelve million, two hundred thirty-one thousand, three hundred seventeen".