Base | Representation |
---|---|
bin | 101110111011111000111… |
… | …110001000111011001101 |
3 | 102102100022211212020010020 |
4 | 232323320332020323031 |
5 | 410321111020323203 |
6 | 10505421321332353 |
7 | 452012323663062 |
oct | 56737076107315 |
9 | 12370284766106 |
10 | 3225402511053 |
11 | 10339816a4468 |
12 | 4411309370b9 |
13 | 1a5200895ab8 |
14 | b21789bac69 |
15 | 58d77d98153 |
hex | 2eef8f88ecd |
3225402511053 has 8 divisors (see below), whose sum is σ = 4300545302400. Its totient is φ = 2150264030208.
The previous prime is 3225402511049. The next prime is 3225402511091. The reversal of 3225402511053 is 3501152045223.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3225402511053 - 22 = 3225402511049 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3225402511033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1666828 + ... + 3037946.
It is an arithmetic number, because the mean of its divisors is an integer number (537568162800).
Almost surely, 23225402511053 is an apocalyptic number.
It is an amenable number.
3225402511053 is a deficient number, since it is larger than the sum of its proper divisors (1075142791347).
3225402511053 is a wasteful number, since it uses less digits than its factorization.
3225402511053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2155251.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 3225402511053 its reverse (3501152045223), we get a palindrome (6726554556276).
The spelling of 3225402511053 in words is "three trillion, two hundred twenty-five billion, four hundred two million, five hundred eleven thousand, fifty-three".
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