Search a number
-
+
322542325025147 is a prime number
BaseRepresentation
bin100100101010110011011110…
…0101101010100100101111011
31120022000202010012110201010102
41021111212330231110211323
5314234013140201301042
63101553522030510015
7124636625331620243
oct11125467455244573
91508022105421112
10322542325025147
11938544828a7667
1230212a4406530b
1310ac87c2a47b56
1459911bba38b23
1527450ecea3b32
hex12559bcb5497b

322542325025147 has 2 divisors, whose sum is σ = 322542325025148. Its totient is φ = 322542325025146.

The previous prime is 322542325025093. The next prime is 322542325025149. The reversal of 322542325025147 is 741520523245223.

It is a strong prime.

It is an emirp because it is prime and its reverse (741520523245223) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 322542325025147 - 210 = 322542325024123 is a prime.

Together with 322542325025149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (322542325025149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161271162512573 + 161271162512574.

It is an arithmetic number, because the mean of its divisors is an integer number (161271162512574).

Almost surely, 2322542325025147 is an apocalyptic number.

322542325025147 is a deficient number, since it is larger than the sum of its proper divisors (1).

322542325025147 is an equidigital number, since it uses as much as digits as its factorization.

322542325025147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032000, while the sum is 47.

The spelling of 322542325025147 in words is "three hundred twenty-two trillion, five hundred forty-two billion, three hundred twenty-five million, twenty-five thousand, one hundred forty-seven".