Base | Representation |
---|---|
bin | 101110111111010010101… |
… | …010010101100101011001 |
3 | 102102200202101012100100200 |
4 | 232333102222111211121 |
5 | 410401101004044423 |
6 | 10511223545452413 |
7 | 452201662351110 |
oct | 56772252254531 |
9 | 12380671170320 |
10 | 3229054753113 |
11 | 1035486254a32 |
12 | 44198baa1109 |
13 | 1a5663437987 |
14 | b2403a88c77 |
15 | 58edd828d43 |
hex | 2efd2a95959 |
3229054753113 has 12 divisors (see below), whose sum is σ = 5330503084608. Its totient is φ = 1845174144600.
The previous prime is 3229054753073. The next prime is 3229054753153. The reversal of 3229054753113 is 3113574509223.
3229054753113 is a `hidden beast` number, since 3 + 2 + 2 + 90 + 547 + 5 + 3 + 1 + 13 = 666.
It is an interprime number because it is at equal distance from previous prime (3229054753073) and next prime (3229054753153).
It is not a de Polignac number, because 3229054753113 - 217 = 3229054622041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3229054753153) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25627418613 + ... + 25627418738.
It is an arithmetic number, because the mean of its divisors is an integer number (444208590384).
Almost surely, 23229054753113 is an apocalyptic number.
It is an amenable number.
3229054753113 is a deficient number, since it is larger than the sum of its proper divisors (2101448331495).
3229054753113 is a wasteful number, since it uses less digits than its factorization.
3229054753113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51254837364 (or 51254837361 counting only the distinct ones).
The product of its (nonzero) digits is 680400, while the sum is 45.
The spelling of 3229054753113 in words is "three trillion, two hundred twenty-nine billion, fifty-four million, seven hundred fifty-three thousand, one hundred thirteen".
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