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3230310000113 = 73660712606137
BaseRepresentation
bin101111000000011101011…
…110101110010111110001
3102102210222212011111112022
4233000131132232113301
5410411133330000423
610511552310041225
7452245043646260
oct57003536562761
912383885144468
103230310000113
111035a6a865649
12442080349215
131a5803503891
14b24c267a5d7
1559063b28dc8
hex2f01d7ae5f1

3230310000113 has 8 divisors (see below), whose sum is σ = 3691883999232. Its totient is φ = 2768761286496.

The previous prime is 3230310000089. The next prime is 3230310000173. The reversal of 3230310000113 is 3110000130323.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3230310000113 - 220 = 3230308951537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3230310000091 and 3230310000100.

It is not an unprimeable number, because it can be changed into a prime (3230310000173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6046820 + ... + 6559317.

It is an arithmetic number, because the mean of its divisors is an integer number (461485499904).

Almost surely, 23230310000113 is an apocalyptic number.

It is an amenable number.

3230310000113 is a deficient number, since it is larger than the sum of its proper divisors (461573999119).

3230310000113 is a wasteful number, since it uses less digits than its factorization.

3230310000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12642751.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 3230310000113 its reverse (3110000130323), we get a palindrome (6340310130436).

The spelling of 3230310000113 in words is "three trillion, two hundred thirty billion, three hundred ten million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 7 36607 256249 12606137 88242959 461472857159 3230310000113