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323100121231 is a prime number
BaseRepresentation
bin1001011001110100100…
…01001001100010001111
31010212222101212202211201
410230322101021202033
520243202112334411
6404232524530331
732225502500506
oct4547221114217
91125871782751
10323100121231
11115031660288
12527516b09a7
13246118747b4
14118d105383d
1586106993c1
hex4b3a44988f

323100121231 has 2 divisors, whose sum is σ = 323100121232. Its totient is φ = 323100121230.

The previous prime is 323100121187. The next prime is 323100121247. The reversal of 323100121231 is 132121001323.

It is a strong prime.

It is an emirp because it is prime and its reverse (132121001323) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 323100121231 - 215 = 323100088463 is a prime.

It is a super-2 number, since 2×3231001212312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 323100121199 and 323100121208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (323100121271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161550060615 + 161550060616.

It is an arithmetic number, because the mean of its divisors is an integer number (161550060616).

Almost surely, 2323100121231 is an apocalyptic number.

323100121231 is a deficient number, since it is larger than the sum of its proper divisors (1).

323100121231 is an equidigital number, since it uses as much as digits as its factorization.

323100121231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 323100121231 its reverse (132121001323), we get a palindrome (455221122554).

The spelling of 323100121231 in words is "three hundred twenty-three billion, one hundred million, one hundred twenty-one thousand, two hundred thirty-one".