323112023000131 has 4 divisors (see below), whose sum is σ = 342118612588392. Its totient is φ = 304105433411872.

The previous prime is 323112023000069. The next prime is 323112023000147. The reversal of 323112023000131 is 131000320211323.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 323112023000131 - 2³⁷ = 322974584046659 is a prime.

It is a super-3 number, since 3×323112023000131³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (323112003000131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9503294794105 + ... + 9503294794138.

It is an arithmetic number, because the mean of its divisors is an integer number (85529653147098).

Almost surely, 2^{323112023000131} is an apocalyptic number.

323112023000131 is a deficient number, since it is larger than the sum of its proper divisors (19006589588261).

323112023000131 is a wasteful number, since it uses less digits than its factorization.

323112023000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19006589588260.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 323112023000131 its reverse (131000320211323), we get a palindrome (454112343211454).

The spelling of 323112023000131 in words is "three hundred twenty-three trillion, one hundred twelve billion, twenty-three million, one hundred thirty-one", and thus it is an aban number.