Base | Representation |
---|---|
bin | 100100101111000000111100… |
… | …1000110010010001011011011 |
3 | 1120101002001210211210111112221 |
4 | 1021132001321012102023123 |
5 | 314323003312343200011 |
6 | 3103115424322044511 |
7 | 125026502611050106 |
oct | 11136017106221333 |
9 | 1511061724714487 |
10 | 323121011303131 |
11 | 93a57940151368 |
12 | 302a7024aa9737 |
13 | 10b3b246a99a12 |
14 | 59b11d734373d |
15 | 27551bbaa4971 |
hex | 125e0791922db |
323121011303131 has 4 divisors (see below), whose sum is σ = 334263115141200. Its totient is φ = 311978907465064.
The previous prime is 323121011303053. The next prime is 323121011303141. The reversal of 323121011303131 is 131303110121323.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-323121011303131 is a prime.
It is a super-2 number, since 2×3231210113031312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 323121011303096 and 323121011303105.
It is not an unprimeable number, because it can be changed into a prime (323121011303141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5571051918991 + ... + 5571051919048.
It is an arithmetic number, because the mean of its divisors is an integer number (83565778785300).
Almost surely, 2323121011303131 is an apocalyptic number.
323121011303131 is a deficient number, since it is larger than the sum of its proper divisors (11142103838069).
323121011303131 is a wasteful number, since it uses less digits than its factorization.
323121011303131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11142103838068.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 323121011303131 its reverse (131303110121323), we get a palindrome (454424121424454).
The spelling of 323121011303131 in words is "three hundred twenty-three trillion, one hundred twenty-one billion, eleven million, three hundred three thousand, one hundred thirty-one".
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