3231254041 has 4 divisors (see below), whose sum is σ = 3237730000. Its totient is φ = 3224778084.

The previous prime is 3231254027. The next prime is 3231254051. The reversal of 3231254041 is 1404521323.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1404521323 = 2297 ⋅611459.

It is a cyclic number.

It is not a de Polignac number, because 3231254041 - 2¹¹ = 3231251993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3231253997 and 3231254015.

It is not an unprimeable number, because it can be changed into a prime (3231254011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3237231 + ... + 3238228.

It is an arithmetic number, because the mean of its divisors is an integer number (809432500).

Almost surely, 2^3231254041 is an apocalyptic number.

It is an amenable number.

3231254041 is a deficient number, since it is larger than the sum of its proper divisors (6475959).

3231254041 is an equidigital number, since it uses as much as digits as its factorization.

3231254041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6475958.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 3231254041 is about 56844.1205490946. The cubic root of 3231254041 is about 1478.3946009707.

Adding to 3231254041 its reverse (1404521323), we get a palindrome (4635775364).

The spelling of 3231254041 in words is "three billion, two hundred thirty-one million, two hundred fifty-four thousand, forty-one".