Base | Representation |
---|---|
bin | 1110101100011100001101… |
… | …11001101011000000011001 |
3 | 11020102010021120222002112210 |
4 | 13112032012321223000121 |
5 | 13213410120332424423 |
6 | 152420305350225333 |
7 | 6543362516054436 |
oct | 726160671530031 |
9 | 136363246862483 |
10 | 32313302233113 |
11 | a328aa3782820 |
12 | 375a64b655249 |
13 | 15051926a4275 |
14 | 7d9d878dcb8d |
15 | 3b08231b7b93 |
hex | 1d6386e6b019 |
32313302233113 has 32 divisors (see below), whose sum is σ = 47256333667200. Its totient is φ = 19477550039040.
The previous prime is 32313302233103. The next prime is 32313302233129. The reversal of 32313302233113 is 31133220331323.
It is not a de Polignac number, because 32313302233113 - 24 = 32313302233097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (32313302233103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25318113 + ... + 26563761.
It is an arithmetic number, because the mean of its divisors is an integer number (1476760427100).
Almost surely, 232313302233113 is an apocalyptic number.
32313302233113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
32313302233113 is a deficient number, since it is larger than the sum of its proper divisors (14943031434087).
32313302233113 is a wasteful number, since it uses less digits than its factorization.
32313302233113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1249929.
The product of its (nonzero) digits is 17496, while the sum is 30.
Adding to 32313302233113 its reverse (31133220331323), we get a palindrome (63446522564436).
The spelling of 32313302233113 in words is "thirty-two trillion, three hundred thirteen billion, three hundred two million, two hundred thirty-three thousand, one hundred thirteen".
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