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3231331120049 is a prime number
BaseRepresentation
bin101111000001011010010…
…101111111001110110001
3102102220122000120202202012
4233001122111333032301
5410420231231320144
610512241504132305
7452312253222314
oct57013225771661
912386560522665
103231331120049
1110364441a411a
12442306307095
131a5936c26b66
14b257c12497b
15590c35cce9e
hex2f05a57f3b1

3231331120049 has 2 divisors, whose sum is σ = 3231331120050. Its totient is φ = 3231331120048.

The previous prime is 3231331119983. The next prime is 3231331120051. The reversal of 3231331120049 is 9400211331323.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2991983170225 + 239347949824 = 1729735^2 + 489232^2 .

It is an emirp because it is prime and its reverse (9400211331323) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3231331120049 - 216 = 3231331054513 is a prime.

Together with 3231331120051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3231331119997 and 3231331120024.

It is not a weakly prime, because it can be changed into another prime (3231331120079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1615665560024 + 1615665560025.

It is an arithmetic number, because the mean of its divisors is an integer number (1615665560025).

Almost surely, 23231331120049 is an apocalyptic number.

It is an amenable number.

3231331120049 is a deficient number, since it is larger than the sum of its proper divisors (1).

3231331120049 is an equidigital number, since it uses as much as digits as its factorization.

3231331120049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 32.

The spelling of 3231331120049 in words is "three trillion, two hundred thirty-one billion, three hundred thirty-one million, one hundred twenty thousand, forty-nine".