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323212320148447 is a prime number
BaseRepresentation
bin100100101111101011011101…
…1100001111000101111011111
31120101101210111022111102220201
41021133112323201320233133
5314331002312424222242
63103225405015324331
7125036214412324162
oct11137267341705737
91511353438442821
10323212320148447
1193a926366612a4
12303008680806a7
1310b46a38b03082
1459b57b9dc5ad9
152757762cbc4b7
hex125f5bb878bdf

323212320148447 has 2 divisors, whose sum is σ = 323212320148448. Its totient is φ = 323212320148446.

The previous prime is 323212320148373. The next prime is 323212320148451. The reversal of 323212320148447 is 744841023212323.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 323212320148447 - 215 = 323212320115679 is a prime.

It is a super-2 number, since 2×3232123201484472 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 323212320148397 and 323212320148406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (323212320145447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161606160074223 + 161606160074224.

It is an arithmetic number, because the mean of its divisors is an integer number (161606160074224).

Almost surely, 2323212320148447 is an apocalyptic number.

323212320148447 is a deficient number, since it is larger than the sum of its proper divisors (1).

323212320148447 is an equidigital number, since it uses as much as digits as its factorization.

323212320148447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1548288, while the sum is 46.

The spelling of 323212320148447 in words is "three hundred twenty-three trillion, two hundred twelve billion, three hundred twenty million, one hundred forty-eight thousand, four hundred forty-seven".