Base | Representation |
---|---|
bin | 1110101100111011010111… |
… | …11101110110101111010111 |
3 | 11020110201110101121120112021 |
4 | 13112131223331312233113 |
5 | 13214143400213322403 |
6 | 152432113313034011 |
7 | 6544524200415346 |
oct | 726355375665727 |
9 | 136421411546467 |
10 | 32330030214103 |
11 | a3350a82394a6 |
12 | 3761939855907 |
13 | 150692a21587b |
14 | 7daad340db5d |
15 | 3b0ea1a5b8bd |
hex | 1d676bf76bd7 |
32330030214103 has 4 divisors (see below), whose sum is σ = 32354393463520. Its totient is φ = 32305666964688.
The previous prime is 32330030214101. The next prime is 32330030214127. The reversal of 32330030214103 is 30141203003323.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32330030214103 - 21 = 32330030214101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32330030214101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12181622718 + ... + 12181625371.
It is an arithmetic number, because the mean of its divisors is an integer number (8088598365880).
Almost surely, 232330030214103 is an apocalyptic number.
32330030214103 is a deficient number, since it is larger than the sum of its proper divisors (24363249417).
32330030214103 is a wasteful number, since it uses less digits than its factorization.
32330030214103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24363249416.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 32330030214103 its reverse (30141203003323), we get a palindrome (62471233217426).
The spelling of 32330030214103 in words is "thirty-two trillion, three hundred thirty billion, thirty million, two hundred fourteen thousand, one hundred three".
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