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323311333040089 is a prime number
BaseRepresentation
bin100100110000011001100100…
…1001010000101111111011001
31120101202021001200201111001121
41021200303021022011333121
5314334113102224240324
63103343102001245241
7125046321142113562
oct11140631112057731
91511667050644047
10323311333040089
1194020625879269
1230317a9b333821
1310b53187c6a414
1459ba4cdcd3169
15275a10a5205e4
hex1260cc9285fd9

323311333040089 has 2 divisors, whose sum is σ = 323311333040090. Its totient is φ = 323311333040088.

The previous prime is 323311333039991. The next prime is 323311333040147. The reversal of 323311333040089 is 980040333113323.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 323131794401689 + 179538638400 = 17975867^2 + 423720^2 .

It is a cyclic number.

It is not a de Polignac number, because 323311333040089 - 29 = 323311333039577 is a prime.

It is a super-2 number, since 2×3233113330400892 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (323311333046089) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161655666520044 + 161655666520045.

It is an arithmetic number, because the mean of its divisors is an integer number (161655666520045).

Almost surely, 2323311333040089 is an apocalyptic number.

It is an amenable number.

323311333040089 is a deficient number, since it is larger than the sum of its proper divisors (1).

323311333040089 is an equidigital number, since it uses as much as digits as its factorization.

323311333040089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 43.

The spelling of 323311333040089 in words is "three hundred twenty-three trillion, three hundred eleven billion, three hundred thirty-three million, forty thousand, eighty-nine".