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323312312209981 is a prime number
BaseRepresentation
bin100100110000011010000001…
…1100001010101001000111101
31120101202100120221012110122011
41021200310003201111020331
5314334122103411204411
63103343343100251221
7125046354331660363
oct11140640341251075
91511670527173564
10323312312209981
1194020a88565086
1230318113240b11
1310b532b2a933a3
1459ba583d7b633
15275a166489c21
hex1260d0385523d

323312312209981 has 2 divisors, whose sum is σ = 323312312209982. Its totient is φ = 323312312209980.

The previous prime is 323312312209921. The next prime is 323312312210087. The reversal of 323312312209981 is 189902213213323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 279180989864100 + 44131322345881 = 16708710^2 + 6643141^2 .

It is a cyclic number.

It is not a de Polignac number, because 323312312209981 - 237 = 323174873256509 is a prime.

It is a super-3 number, since 3×3233123122099813 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (323312312209921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161656156104990 + 161656156104991.

It is an arithmetic number, because the mean of its divisors is an integer number (161656156104991).

Almost surely, 2323312312209981 is an apocalyptic number.

It is an amenable number.

323312312209981 is a deficient number, since it is larger than the sum of its proper divisors (1).

323312312209981 is an equidigital number, since it uses as much as digits as its factorization.

323312312209981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 839808, while the sum is 49.

The spelling of 323312312209981 in words is "three hundred twenty-three trillion, three hundred twelve billion, three hundred twelve million, two hundred nine thousand, nine hundred eighty-one".