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32340128000000 = 2115619431237
BaseRepresentation
bin1110101101001110001011…
…10101110110100000000000
311020111200112010101020200112
413112213011311312200000
513214330040232000000
6152440503311410452
76545332343241362
oct726470565664000
9136450463336615
1032340128000000
11a33940a1724a7
123763897523a28
13150787924cb02
147db3b0548d32
153b13932d3235
hex1d69c5d76800

32340128000000 has 672 divisors, whose sum is σ = 87132806560800. Its totient is φ = 11960524800000.

The previous prime is 32340127999987. The next prime is 32340128000021. The reversal of 32340128000000 is 82104323.

It is a super-3 number, since 3×323401280000003 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 32340128000000.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 26143999382 + ... + 26144000618.

It is an arithmetic number, because the mean of its divisors is an integer number (129661914525).

Almost surely, 232340128000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 32340128000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (43566403280400).

32340128000000 is an abundant number, since it is smaller than the sum of its proper divisors (54792678560800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32340128000000 is an frugal number, since it uses more digits than its factorization.

32340128000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1351 (or 1306 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

The spelling of 32340128000000 in words is "thirty-two trillion, three hundred forty billion, one hundred twenty-eight million", and thus it is an aban number.