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32344004334493 is a prime number
BaseRepresentation
bin1110101101010101011001…
…11000111001001110011101
311020112001112021101102221201
413112222230320321032131
513214411010102200433
6152442344102555501
76545530402446205
oct726525470711635
9136461467342851
1032344004334493
11a340019270a25
123764599738b91
131508046363067
147db65b2ab405
153b151d77ba7d
hex1d6aace3939d

32344004334493 has 2 divisors, whose sum is σ = 32344004334494. Its totient is φ = 32344004334492.

The previous prime is 32344004334409. The next prime is 32344004334563. The reversal of 32344004334493 is 39443340044323.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22185588384964 + 10158415949529 = 4710158^2 + 3187227^2 .

It is an emirp because it is prime and its reverse (39443340044323) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32344004334493 - 217 = 32344004203421 is a prime.

It is a super-2 number, since 2×323440043344932 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32344004334793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16172002167246 + 16172002167247.

It is an arithmetic number, because the mean of its divisors is an integer number (16172002167247).

Almost surely, 232344004334493 is an apocalyptic number.

It is an amenable number.

32344004334493 is a deficient number, since it is larger than the sum of its proper divisors (1).

32344004334493 is an equidigital number, since it uses as much as digits as its factorization.

32344004334493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4478976, while the sum is 46.

The spelling of 32344004334493 in words is "thirty-two trillion, three hundred forty-four billion, four million, three hundred thirty-four thousand, four hundred ninety-three".