3240011403133 has 2 divisors, whose sum is σ = 3240011403134. Its totient is φ = 3240011403132.

The previous prime is 3240011403059. The next prime is 3240011403137. The reversal of 3240011403133 is 3313041100423.

3240011403133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2807812976409 + 432198426724 = 1675653^2 + 657418^2 .

It is a cyclic number.

It is not a de Polignac number, because 3240011403133 - 2²⁹ = 3239474532221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3240011403098 and 3240011403107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3240011403137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620005701566 + 1620005701567.

It is an arithmetic number, because the mean of its divisors is an integer number (1620005701567).

Almost surely, 2^{3240011403133} is an apocalyptic number.

It is an amenable number.

3240011403133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3240011403133 is an equidigital number, since it uses as much as digits as its factorization.

3240011403133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3240011403133 its reverse (3313041100423), we get a palindrome (6553052503556).

The spelling of 3240011403133 in words is "three trillion, two hundred forty billion, eleven million, four hundred three thousand, one hundred thirty-three".