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324101230144031 is a prime number
BaseRepresentation
bin100100110110001001011001…
…0101100011010101000011111
31120111112202220222110221001202
41021230102302230122220133
5314440033304404102111
63105150014421430115
7125160353421530264
oct11154226254325037
91514482828427052
10324101230144031
11942a561812968a
1230424ba626b33b
1310bac7cbb10892
145a0682458d26b
15277093b8cbb3b
hex126c4b2b1aa1f

324101230144031 has 2 divisors, whose sum is σ = 324101230144032. Its totient is φ = 324101230144030.

The previous prime is 324101230144019. The next prime is 324101230144049. The reversal of 324101230144031 is 130441032101423.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 324101230144031 - 210 = 324101230143007 is a prime.

It is a super-2 number, since 2×3241012301440312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 324101230143985 and 324101230144003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (324101230144001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162050615072015 + 162050615072016.

It is an arithmetic number, because the mean of its divisors is an integer number (162050615072016).

Almost surely, 2324101230144031 is an apocalyptic number.

324101230144031 is a deficient number, since it is larger than the sum of its proper divisors (1).

324101230144031 is an equidigital number, since it uses as much as digits as its factorization.

324101230144031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 324101230144031 its reverse (130441032101423), we get a palindrome (454542262245454).

The spelling of 324101230144031 in words is "three hundred twenty-four trillion, one hundred one billion, two hundred thirty million, one hundred forty-four thousand, thirty-one".