Base | Representation |
---|---|
bin | 101111001010100000110… |
… | …011010101000000011110 |
3 | 102110211212001101101022102 |
4 | 233022200303111000132 |
5 | 411100234401314014 |
6 | 10520535304445102 |
7 | 453106362141002 |
oct | 57124063250036 |
9 | 12424761341272 |
10 | 3241103151134 |
11 | 103a5a9262772 |
12 | 444192a79792 |
13 | 1a6833616684 |
14 | b2c27ca4702 |
15 | 594964598de |
hex | 2f2a0cd501e |
3241103151134 has 4 divisors (see below), whose sum is σ = 4861654726704. Its totient is φ = 1620551575566.
The previous prime is 3241103151133. The next prime is 3241103151149. The reversal of 3241103151134 is 4311513011423.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 3241103151097 and 3241103151106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3241103151133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 810275787782 + ... + 810275787785.
It is an arithmetic number, because the mean of its divisors is an integer number (1215413681676).
Almost surely, 23241103151134 is an apocalyptic number.
3241103151134 is a deficient number, since it is larger than the sum of its proper divisors (1620551575570).
3241103151134 is a wasteful number, since it uses less digits than its factorization.
3241103151134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1620551575569.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 3241103151134 its reverse (4311513011423), we get a palindrome (7552616162557).
The spelling of 3241103151134 in words is "three trillion, two hundred forty-one billion, one hundred three million, one hundred fifty-one thousand, one hundred thirty-four".
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