Base | Representation |
---|---|
bin | 101111001010101001100… |
… | …111100100100011001101 |
3 | 102110212020100201010122012 |
4 | 233022221213210203031 |
5 | 411101040233022023 |
6 | 10521002111031005 |
7 | 453113136315614 |
oct | 57125147444315 |
9 | 12425210633565 |
10 | 3241251064013 |
11 | 103a6747a9916 |
12 | 44421450b465 |
13 | 1a68581645a1 |
14 | b2c3d7a887b |
15 | 594a4425978 |
hex | 2f2a99e48cd |
3241251064013 has 4 divisors (see below), whose sum is σ = 3241700060160. Its totient is φ = 3240802067868.
The previous prime is 3241251063991. The next prime is 3241251064043. The reversal of 3241251064013 is 3104601521423.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3241251064013 - 216 = 3241250998477 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3241251064043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224487245 + ... + 224501682.
It is an arithmetic number, because the mean of its divisors is an integer number (810425015040).
Almost surely, 23241251064013 is an apocalyptic number.
It is an amenable number.
3241251064013 is a deficient number, since it is larger than the sum of its proper divisors (448996147).
3241251064013 is an equidigital number, since it uses as much as digits as its factorization.
3241251064013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 448996146.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 3241251064013 its reverse (3104601521423), we get a palindrome (6345852585436).
The spelling of 3241251064013 in words is "three trillion, two hundred forty-one billion, two hundred fifty-one million, sixty-four thousand, thirteen".
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