3241410433 has 4 divisors (see below), whose sum is σ = 3243689728. Its totient is φ = 3239131140.

The previous prime is 3241410379. The next prime is 3241410439. The reversal of 3241410433 is 3340141423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3241410433 is a prime.

It is a super-2 number, since 2×3241410433² = 21013483190322494978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3241410398 and 3241410407.

It is not an unprimeable number, because it can be changed into a prime (3241410439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1137513 + ... + 1140358.

It is an arithmetic number, because the mean of its divisors is an integer number (810922432).

Almost surely, 2^3241410433 is an apocalyptic number.

It is an amenable number.

3241410433 is a deficient number, since it is larger than the sum of its proper divisors (2279295).

3241410433 is a wasteful number, since it uses less digits than its factorization.

3241410433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2279294.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 3241410433 is about 56933.3859260101. The cubic root of 3241410433 is about 1479.9419311585.

Adding to 3241410433 its reverse (3340141423), we get a palindrome (6581551856).

The spelling of 3241410433 in words is "three billion, two hundred forty-one million, four hundred ten thousand, four hundred thirty-three".