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3242022013141 is a prime number
BaseRepresentation
bin101111001011010111100…
…100100000100011010101
3102110221020002101102000121
4233023113210200203111
5411104130113410031
610521210411111541
7453141220265662
oct57132744404325
912427202342017
103242022013141
11103aa2a9a835a
124443aa7425b1
131a694bab54c2
14b2cb3d30a69
15594ebe60011
hex2f2d79208d5

3242022013141 has 2 divisors, whose sum is σ = 3242022013142. Its totient is φ = 3242022013140.

The previous prime is 3242022013037. The next prime is 3242022013147. The reversal of 3242022013141 is 1413102202423.

3242022013141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3234638220100 + 7383793041 = 1798510^2 + 85929^2 .

It is a cyclic number.

It is not a de Polignac number, because 3242022013141 - 211 = 3242022011093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3242022013147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1621011006570 + 1621011006571.

It is an arithmetic number, because the mean of its divisors is an integer number (1621011006571).

Almost surely, 23242022013141 is an apocalyptic number.

It is an amenable number.

3242022013141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3242022013141 is an equidigital number, since it uses as much as digits as its factorization.

3242022013141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 3242022013141 its reverse (1413102202423), we get a palindrome (4655124215564).

The spelling of 3242022013141 in words is "three trillion, two hundred forty-two billion, twenty-two million, thirteen thousand, one hundred forty-one".